Tweet 142 by Oaxiiboo 6: We only ask that you keep every information in context and do not introduce any change, truncation or addition. Report every information in a specific format distinguishable from any comment or speculation you might make.

Following this request in tweet 142 by OAXIIBOO 6, we have tried to find the question to which @oolga_waam replies, and we have always highlighted the original text in blue bold while translations are in blue italics.
The original page is in Spanish; in this English version, Spanish translations of texts already in English have been omitted, and only texts in other languages are translated (in italics).
Our comments are always in olive-green italics.

QUICK ACCESS TO THE TWEETS OF OOLGA WAAM:

@oolga_waam
Sorrow for all the people who died and suffer in Nepal.
http://mashable.com/2015/04/25/nepal-earthquake/?utm_cid=hp-hh-pri

@AlexVercors 25 Apr 2015

Welcome to you ! Here to talk about cosmology ? @oomo_toa Have a nice stay among us

@oolga_waam 27 Apr 2015
Thank you. Yes.

@AlexVercors 27 Apr 2015

Hello ! "Was there" a big bang ? Does the concept of big bang make sense ? Are today's cosmologists on a good path ?

@oolga_waam
You must expand its meaning to an infinity of universes.
WAAM WAAM, then undissociated, began to split into distinct sub parts.

@manuelOtroMundo 29 Apr 2015

No acabo de entender la presentación que hacen de su modelo matemático del W-W en sus tweets 65 y 67.
Gracias

@oolga_waam
Los tres ejes espaciales están articulados/ligados al eje T, que tiene por su parte un solo grado de libertad rotacional x 2π.

I don't quite understand the presentation you give of your mathematical model of the W-W in your tweets 65 and 67.
Thank you

The three spatial axes are articulated/linked to the T axis, which for its part has a single rotational degree of freedom x 2π.

@pepetmurri

Cómo calculan el 10^495 = ((10^11)^9)^5, de twit 65 de O6? 10^11 por cada ángulo. ( 10^11)^9 OK. El 5?

@oolga_waam
(10^11)^9=10^99.
10^99*10^88*10^77*10^66*10^55*10^44*10^33*10^22*10^11 = 10^495 potencialidades de WAAM.

How do you calculate the 10^495 = ((10^11)^9)^5 in tweet 65 by O6? 10^11 for each angle. (10^11)^9 OK. The 5?

(10^11)^9=10^99.
10^99*10^88*10^77*10^66*10^55*10^44*10^33*10^22*10^11 = 10^495 potentialities of WAAM.

@manuelOtroMundo 4 May 2015

Pf. cuantos OAWO son necesarios para expresar cada uno de los triedros? 4? Y para el tiempo? 2? => IU tiene 14 OAWO?

@oolga_waam 7 May 2015
Se necesita de un OAWO generador referente W para definir cada triedro, (∠(x,W)=α, ∠(y,W)=β, ∠(z,W)=γ). Y otro también para T.

Please: how many OAWO are needed to express each of the trihedra? 4? And for time? 2? => does IU have 14 OAWO?

A generating reference OAWO W is needed to define each trihedron (∠(x,W)=α, ∠(y,W)=β, ∠(z,W)=γ). And another one for T as well.

OOLGA WAAM retweeted
Nautilus @NautilusMag 28 Apr 2015
Is our universe a one-off fluke or an endless cycle?
@brianscottg asks Paul Steinhardt.
http://go.nautil.us/oneoff

OOLGA WAAM retweeted 14 May 2015
Our universe could be 'one bubble in a frothy sea of bubbles'
http://dailym.ai/UgtZET via @MailOnline

OOLGA WAAM retweeted
STRING THEORY 10 X 10^500 MULTIVERSE
SIMULATION: Alan Guth Are We Living in a Simulation (1D time)?
http://www.youtube.com/watch?v=NeUfqnCPDC4&sns=tw … via @youtube